Thread #16922560
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H
just do it by how long its decimal expression is
for simplicity I'll be sticking to reels from 0 to 1
first count all 1 digit numbers, then 2 digit numbers the three digit numbers, etc.

countable ... uncountable
01 -> 0.1
02 -> 0.2
03 -> 0.3
04 -> 0.4
05 -> 0.5
06 -> 0.6
07 -> 0.7
08 -> 0.8
09 -> 0.9
10 -> 0.00
11 -> 0.01
12 -> 0.02
13 -> 0.03
14 -> 0.04
15 -> 0.05
16 -> 0.06
17 -> 0.07
...
99 -> 0.99
100 -> 0.000
101 -> 0.001


might even write a .py file for this
wait, nevermind just saw a problem
whatever I'll post it anyway anons do the rest
+Showing all 4 replies.
>>
define every number as an offset into pi
>>
>>16922563
even easier, define every real number as an offset into champernowne's constant (0.12345678910111213...)
Champ has all numbers, so it would work but only with cutoffs
and a number's position within Champ can be directly computed.
>>
let U be the set of all uncountable numbers
>>
If X is the smallest uncountable number, then X + 1 is the next smallest uncountable number, and you can count them so on and so forth until they become uncountably uncountable.

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